(x-1)(x^2-x-12)=0

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Solution for (x-1)(x^2-x-12)=0 equation: 


Simplifying
(x + -1)(x2 + -1x + -12) = 0

Reorder the terms:
(-1 + x)(x2 + -1x + -12) = 0

Reorder the terms:
(-1 + x)(-12 + -1x + x2) = 0

Multiply (-1 + x) * (-12 + -1x + x2)
(-1(-12 + -1x + x2) + x(-12 + -1x + x2)) = 0
((-12 * -1 + -1x * -1 + x2 * -1) + x(-12 + -1x + x2)) = 0
((12 + 1x + -1x2) + x(-12 + -1x + x2)) = 0
(12 + 1x + -1x2 + (-12 * x + -1x * x + x2 * x)) = 0
(12 + 1x + -1x2 + (-12x + -1x2 + x3)) = 0

Reorder the terms:
(12 + 1x + -12x + -1x2 + -1x2 + x3) = 0

Combine like terms: 1x + -12x = -11x
(12 + -11x + -1x2 + -1x2 + x3) = 0

Combine like terms: -1x2 + -1x2 = -2x2
(12 + -11x + -2x2 + x3) = 0

Solving
12 + -11x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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